Free Body Diagram

Free Body Diagram | A block rest on horizontal Surface | Learn begginer to Advance Study | Part: 1

👉A block rest on a frictionless horizontal surface and the blocked pulled horizontally with a force \(F\).

From the free body diagram, here we get,
\(R = mg\) and
\({F_{net}} = ma\)

👉A block rest on a horizontal surface where coefficient of friction between block and the surface is \(\mu \) and the block pulled horizontally with a force \(F\)

From the free body diagram we get,
\(R = mg\) and

\(F - f = ma\)
or, \(F - \mu mg = ma\)
or, \(a = \frac{{F - \mu mg}}{{ma}}\)

👉A block rest on a horizontal surface and a pull is acting at an angle \(\theta \) to the horizontal in upward direction.

From the free body diagram we get,
\(R + F\sin \theta = mg\)
or, \(R = mg - F\sin \theta \) and

the net effective force on the block along horizontal direction is \(F\cos \theta \).
Therefore, \(F\cos \theta = ma\)
or, \(a = \frac{{F\cos \theta }}{m}\)

👉A block rest on a horizontal plane and a pushing force \(F\) acts downward direction at an angle \(\theta \) to the horizontal.

From the free body diagram we get,
\(R = mg\sin \theta + mg\) and

net effective force of the block along horizontal direction is \(F\cos \theta \).
Therefore, \(F\cos \theta = ma\)
or, \(a = \frac{{F\cos \theta }}{m}\)